JEE Main 2026 — Apr 2, Shift 1 — Physics solution

JEE Main2026Apr 2, Shift 1Physics

Angular momentum of an electron in a hydrogen atom is $\frac{3 h}{π}$ , then the energy of the electron is ____ eV.

Solution

Bohr's quantisation rule: $L = \frac{nh}{2 π}$ . Equating to the given value:

$\frac{3 h}{π} = \frac{nh}{2 π} \Rightarrow n = 6$

Energy of the $n$ -th level in hydrogen: $E_{n} = - \frac{13.6}{n ^{2}}$ eV $= - \frac{13.6}{36} \approx - 0.38$ eV.

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