JEE Main 2026 — Apr 2, Shift 2 — Physics solution

JEE Main2026Apr 2, Shift 2Physics

Using Bohr's model, calculate the ratio of the magnetic fields generated due to the motion of the electrons in the $2^{nd}$ and $4^{th}$ orbits of hydrogen atom__.

Your answer

Solution

$B = \frac{μ _{0} I}{2 π r}$

$I = \frac{e v}{2 π r}$

$B \propto \frac{V}{r ^{2}}$

$V \propto \frac{Z}{n}$

$r \propto \frac{n ^{2}}{Z}$

$B\propto \dfrac{\left(\dfrac{Z}{n}\right)} {\left(\dfrac{n^2}{Z}\right)^2}$

$B \propto \frac{Z ^{3}}{n ^{5}}$

$\dfrac{B_1}{B_2} = \dfrac{n_2^5}{n_1^5} = \dfrac{4^5}{2^5} = 64$

← Back to full paper

Practice more Physics

Concept-wise practice with instant solutions on Fundamenthol.

Start practicing →