JEE Main 2026 Apr 2 Shift 2, Physics Q23: Law of Equipartition of Energy

JEE Main2026Apr 2, Shift 2Physics

$5$ moles of unknown gas is heated at constant volume from $1 0^{\circ}$ C to $2 0^{\circ}$ C. The molar specific heat of this gas at constant pressure $c_{p} = 8$ cal/mol. $^{\circ}$ C and $R = 8.36$ J/mol. $^{\circ}$ C. The change in the internal energy of the gas is ____ calorie.

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Solution

Using Mayer's relation in calorie units ( $R \approx 2$ cal/mol $^{\circ}$ C): $C_{V} = C_{P} - R = 8 - 2 = 6$ cal/mol $^{\circ}$ C.

$Δ U = n C_{V} Δ T = 5 \cdot 6 \cdot (20 - 10) = 300$ cal.

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JEE Main 2026 Apr 2 Shift 2, Physics Q23: Law of Equipartition of Energy

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