JEE Main 2026 — Apr 2, Shift 2 — Chemistry solution

JEE Main2026Apr 2, Shift 2Chemistry

SF $_{4}$ is isostructural with :

A. BrF $_{4}^{⊖}$

B. CH $_{4}$

C. IF $_{4}^{\oplus}$

D. XeF $_{4}$

E. XeO $_{2}$ F $_{2}$

Choose the correct answer from the options given below :

A
C only
B
C and E only
C
A and D only
D
B and E only

Solution

SF $_{4}$ has $5$ electron pairs around S ( $4$ bond pairs and $1$ lone pair), giving a trigonal-bipyramidal electron geometry and a see-saw molecular shape (AX $_{4}$ E).

Comparing shapes:

IF $_{4}^{+}$ : $4$ bond pairs and $1$ lone pair on I — also see-saw. $✓$

XeO $_{2}$ F $_{2}$ : $4$ bond pairs (counting the Xe $=$ O double bonds as one region each) and $1$ lone pair on Xe — also see-saw. $✓$

BrF $_{4}^{-}$ and XeF $_{4}$ both have $2$ lone pairs and adopt square-planar geometry.

CH $_{4}$ is tetrahedral.

Hence SF $_{4}$ is isostructural with IF $_{4}^{+}$ and XeO $_{2}$ F $_{2}$ — option (2).

← Back to full paper

Practice more Chemistry

Concept-wise practice with instant solutions on Fundamenthol.

Start practicing →