JEE Main 2026 Apr 4 Shift 2, Physics Q4: Motion In Two And Three Dimension

JEE Main2026Apr 4, Shift 2Physics

If x and y coordinates of a projectile as a function of time (t) are given as $24 t$ and $43.6 t - 4.9 t^{2}$ , respectively, then the angle (in degrees) made by the projectile with horizontal when $t = 2$ s is ________.

A
60
B
45
C
30
D
75

Solution

Differentiate to obtain the velocity components.

$v_{x} = \frac{d x}{d t} = 24 m/s$ (constant).

$v_{y} = \frac{d y}{d t} = 43.6 - 9.8 t m/s$ .

At $t = 2$ s: $v_{y} = 43.6 - 19.6 = 24 m/s$ .

$tan θ = \frac{v _{y}}{v _{x}} = \frac{24}{24} = 1 \Rightarrow θ = 4 5^{\circ}$ .

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JEE Main 2026 Apr 4 Shift 2, Physics Q4: Motion In Two And Three Dimension

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