JEE Main 2026 — Apr 5, Shift 1 — Physics solution

JEE Main2026Apr 5, Shift 1Physics

Refer to the figure given below. The values of $I_{1}$ , $I_{2}$ and $I_{3}$ are ___________.

Solution

Apply Kirchhoff's voltage law on three independent loops, taking $I_{1}$ , $I_{2}$ , $I_{3}$ as marked.

Loop 1 (left upper): $- 4 (I_{1} - I_{3}) - 2 (I_{1} + I_{2} - I_{3}) - I_{1} + 10 = 0$ , i.e. $- 7 I_{1} - 2 I_{2} + 6 I_{3} + 10 = 0$ .

Loop 2 (right): $- 5 - 2 (I_{3} - I_{2}) + 2 (I_{1} + I_{2} - I_{3}) = 0$ , i.e. $2 I_{1} + 4 I_{2} - 4 I_{3} = 5$ .

Loop 3 (left lower): $- I_{1} + 10 - 4 I_{3} - 2 (I_{3} - I_{2}) = 0$ , i.e. $- I_{1} + 2 I_{2} - 6 I_{3} + 10 = 0$ .

Solving this $3 \times 3$ system yields $I_{1} = 2.5$ A, $I_{2} = 1.875$ A, $I_{3} = 1.875$ A.

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