JEE Main 2026 — Apr 5, Shift 1 — Chemistry solution

JEE Main2026Apr 5, Shift 1Chemistry

Correct statements from the following are :

A. Nitrogen in oxidation states from +1 to +4 disproportionates in acid medium.

B. Nitrogen has the ability to form $d_{π} - p_{π}$ multiple bonds with itself and other elements with small size and high electronegativity.

C. N-N single bond is stronger than P-P single bond.

D. Nitrogen has highest density in its group due to small size.

E. The maximum covalency of nitrogen is four since it has only four valence orbitals for bonding.

Choose the correct answer from the options given below :

A
B, C, and D only
B
C, D, and E only
C
A, C and E only
D
A and E only

Solution

A: All intermediate oxidation states of nitrogen (+1 to +4) tend to disproportionate in acidic media; e.g. $3 HNO_{2} \to HNO_{3} + 2 NO + H_{2} O$ . Correct.

B: Nitrogen has no $d$ orbitals in its valence shell, so $d_{π} - p_{π}$ bonding is not possible for nitrogen; it forms only $p_{π} - p_{π}$ bonds. Incorrect.

C: Because of the very short N-N distance, lone-pair repulsions weaken the single N-N bond relative to P-P. So N-N is weaker, not stronger. Incorrect.

D: Nitrogen is a gas at room temperature and has the lowest density in Group 15. Incorrect.

E: With only four valence orbitals (one $s$ and three $p$ ) and no $d$ orbitals available, the maximum covalency of nitrogen is four. Correct.

Correct combination: A and E.

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