JEE Main 2026 — Apr 5, Shift 1 — Chemistry solution

JEE Main2026Apr 5, Shift 1Chemistry

In an estimation of sulphur by Carius method 0.2 g of the substance gave 0.6 g of BaSO $_{4}$ . The percentage of sulphur in the substance is _____ %.

(Given molar mass in g mol $^{- 1}$ : S = 32, BaSO $_{4}$ = 231)

Your answer

Solution

Every mole of BaSO $_{4}$ corresponds to one mole of sulphur originally present in the sample.

Mass of sulphur in 0.6 g BaSO $_{4}$ $= 0.6 \times \frac{32}{231}$ g.

$% S = \frac{0.6 \times 32}{231 \times 0.2} \times 100 = \frac{1920}{46.2} \approx 41.56%$ , which rounds to $42$ .

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