JEE Main 2026 Apr 5 Shift 2, Physics Q21: Properties of Solids

JEE Main2026Apr 5, Shift 2Physics

A copper wire of length 3 m is stretched by 3 mm by applying an external force. The volume of the wire is $600 \times 1 0^{- 6}$ m $^{3}$ . The elastic potential energy stored in the wire in stretched condition would be _____ J. (Given Young modulus of copper $= 1.1 \times 1 0^{11}$ N/m $^{2}$ )

Your answer

Solution

Elastic potential energy per unit volume $= \frac{1}{2} Y (strain)^{2}$ .

Strain $= \frac{Δ L}{L} = \frac{3 \times 1 0 ^{- 3}}{3} = 1 0^{- 3}$ .

$U = \frac{1}{2} \times 1.1 \times 1 0^{11} \times (1 0^{- 3})^{2} \times 600 \times 1 0^{- 6}$

$U = \frac{1}{2} \times 1.1 \times 1 0^{11} \times 1 0^{- 6} \times 6 \times 1 0^{- 4} = 33$ J.

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JEE Main 2026 Apr 5 Shift 2, Physics Q21: Properties of Solids

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