JEE Main 2026 Apr 5 Shift 2, Chemistry Q15: Preparation of Carboxylic acids
JEE Main2026Apr 5, Shift 2Chemistry
Q.
Complete the following reaction sequence and give the name of major product 'P'.

- A
2-Chloropropanoic acid
- B
3-Chloropropanoic acid
- C
1-Chloropropane
- D
2-Chloropropane
Solution

Starting material is propanenitrile, .
Step (i)–(ii): basic hydrolysis followed by acidification converts the nitrile to propanoic acid, .
Step (iii)–(iv): this is the Hell–Volhard–Zelinsky reaction. with a trace of red phosphorus chlorinates at the -carbon, then aqueous workup gives the -chloro acid:
which is 2-chloropropanoic acid.
Concept behind this question
Preparation of Carboxylic acids Notes, formulas and examples →More previous year questions on Preparation of Carboxylic acids
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