JEE Main 2026 Apr 6 Shift 1, Physics Q5: Newton's Laws Of Motion

JEE Main2026Apr 6, Shift 1Physics

A lift of mass $1600$ kg is supported by thick iron wire. If the maximum stress which the wire can withstand is $4 \times 1 0^{8}$ N/m $^{2}$ and its radius is $4$ mm, then maximum acceleration the lift can take is _____ m/s $^{2}$ . (take $g = 10$ m/s $^{2}$ and $π = 3.14$ )

A
$2.56$
B
$3.89$
C
$4.32$
D
$5.16$

Solution

Maximum tension $T_{m a x} = σ_{m a x} \cdot A = (4 \times 1 0^{8}) \cdot π (4 \times 1 0^{- 3})^{2}$ .

$T_{m a x} = 4 \times 1 0^{8} \times 3.14 \times 16 \times 1 0^{- 6} \approx 20096$ N.

Newton's second law for the accelerating lift: $T - m g = ma \Rightarrow a = \frac{T - m g}{m} = \frac{20096 - 16000}{1600} \approx 2.56$ m/s $^{2}$ .

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JEE Main 2026 Apr 6 Shift 1, Physics Q5: Newton's Laws Of Motion

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