JEE Main 2026 Apr 6 Shift 1, Physics Q12: Simple Harmonic Motion And Oscillation

JEE Main2026Apr 6, Shift 1Physics

A particle is executing simple harmonic motion. Its amplitude is $A$ and time period is $5$ sec. The time required by it to move from $x = A$ to $x = \frac{A}{2}$ is____sec.

A
$\frac{1}{4}$
B
$\frac{5}{4}$
C
$\frac{5}{8}$
D
$\frac{3}{8}$

Solution

Use $x (t) = A cos (ω t)$ with start at extreme position $x = A$ ( $t = 0$ ).

Set $A cos (ω t) = \frac{A}{2} \Rightarrow ω t = \frac{π}{4}$ .

$t = \frac{π /4}{ω} = \frac{π /4}{2 π / T} = \frac{T}{8} = \frac{5}{8}$ s.

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JEE Main 2026 Apr 6 Shift 1, Physics Q12: Simple Harmonic Motion And Oscillation

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