JEE Main 2026 Apr 6 Shift 1, Chemistry Q24: Reactions of Various Orders

JEE Main2026Apr 6, Shift 1Chemistry

Sucrose hydrolyses in acidic medium into glucose and fructose by first order rate law with $t_{1/2} = 3$ hour. The percentage of sucrose remaining after $6$ hours is ____. (Nearest integer)

(Given: $lo g 2 = 0.3010$ and $lo g 3 = 0.4771$ )

Your answer

Solution

For a first-order reaction, $t = 6$ h is exactly two half-lives.

After each half-life the fraction remaining is halved:

After $1$ half-life ( $3$ h): $50%$ remains.

After $2$ half-lives ( $6$ h): $25%$ remains.

$∴$ $25%$ of sucrose remains after $6$ hours.

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JEE Main 2026 Apr 6 Shift 1, Chemistry Q24: Reactions of Various Orders

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