JEE Main 2026 Apr 6 Shift 2, Physics Q4: Work Energy Theorem And Its Applications

JEE Main2026Apr 6, Shift 2Physics

A body of mass 1 kg moves along a straight line with a velocity $v = 2 x^{2}$ . The work done by the body during displacement from $x = 0$ to $5$ m is ____ J.

A
0
B
250
C
1250
D
1000

Solution

Apply the work-energy theorem with $m = 1$ kg.

At $x = 0$ : $v_{i} = 2 (0)^{2} = 0$ m/s. At $x = 5$ : $v_{f} = 2 (5)^{2} = 50$ m/s.

$W = Δ K E = \frac{1}{2} m (v_{f}^{2} - v_{i}^{2}) = \frac{1}{2} (1) (5 0^{2} - 0) = 1250$ J.

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JEE Main 2026 Apr 6 Shift 2, Physics Q4: Work Energy Theorem And Its Applications

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