JEE Main 2026 Apr 6 Shift 2, Chemistry Q2: Bohr's Atomic Model

JEE Main2026Apr 6, Shift 2Chemistry

The Bohr radius of a hydrogen like species is 70.53 pm. The species and the stationary state $(n)$ are respectively (Given: Hydrogen atom Bohr radius is 52.9 pm)

A
Li $^{2 +}$ , 3
B
He $^{+}$ , 3
C
He $^{+}$ , 2
D
Li $^{2 +}$ , 2

Solution

Bohr radius: $r_{n} = a_{0} \frac{n ^{2}}{Z}$ .

$\frac{n ^{2}}{Z} = \frac{70.53}{52.9} \approx 1.333 = \frac{4}{3}$ .

This is matched by $n = 2$ and $Z = 3$ , i.e. Li $^{2 +}$ in the second stationary state.

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JEE Main 2026 Apr 6 Shift 2, Chemistry Q2: Bohr's Atomic Model

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