JEE Main 2026 Apr 6 Shift 2, Chemistry Q3: Important Concepts Of Chemical Bonding

JEE Main2026Apr 6, Shift 2Chemistry

Given below are two statements:

Statement I: The number of compounds among SO $_{2}$ , SO $_{3}$ , SF $_{4}$ , SF $_{6}$ and H $_{2}$ S in which sulphur does not obey the octet rule is 3.

Statement II: Among $[$ H $_{2}$ O, ClF $_{3}$ , SF $_{4}]$ , $[$ NH $_{3}$ , BrF $_{5}$ , SF $_{4}]$ , $[$ BrF $_{5}$ , ClF $_{3}$ , XeF $_{4}]$ and $[$ XeF $_{4}$ , ClF $_{3}$ , H $_{2}$ O $]$ , the number of sets in which all the molecules have one lone pair of electrons on the central atom is 1.

In the light of the above statements, choose the correct answer from the options given below:

A
Both Statement I and Statement II are true
B
Both Statement I and Statement II are false
C
Statement I is true Statement II is false
D
Statement I is false Statement II is true

Solution

Statement I. Octet expansion / deviation analysis: SO $_{2}$ (S has 10 e $^{-}$ , expanded), SO $_{3}$ (12), SF $_{4}$ (10), SF $_{6}$ (12) all violate octet; H $_{2}$ S obeys it. That is 4 compounds, not 3. Statement I is false.

Statement II. Lone pairs on the central atom:

H $_{2}$ O (2), ClF $_{3}$ (2), SF $_{4}$ (1), NH $_{3}$ (1), BrF $_{5}$ (1), XeF $_{4}$ (2).

Set 1 $[$ H $_{2}$ O, ClF $_{3}$ , SF $_{4}]$ : lone pairs 2, 2, 1 — not all one.

Set 2 $[$ NH $_{3}$ , BrF $_{5}$ , SF $_{4}]$ : 1, 1, 1 — all one.

Set 3 $[$ BrF $_{5}$ , ClF $_{3}$ , XeF $_{4}]$ : 1, 2, 2 — no.

Set 4 $[$ XeF $_{4}$ , ClF $_{3}$ , H $_{2}$ O $]$ : 2, 2, 2 — no.

Exactly one set qualifies. Statement II is true.

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JEE Main 2026 Apr 6 Shift 2, Chemistry Q3: Important Concepts Of Chemical Bonding

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