JEE Main 2026 Jan 21 Shift 1, Chemistry Q1: Introduction And Nomenclature

JEE Main2026Jan 21, Shift 1Chemistry

Consider the following reactions.

$P b C l_{2} + K_{2} C r O_{4} \to A + 2 K C l$ (Hot solution)

$A + N a O H ⇌ B + N a_{2} C r O_{4}$

$P b S O_{4} + 4 C H_{3} C O O N H_{4} \to (N H_{4})_{2} S O_{4} + X$

In the above reactions, A, B and X are respectively.

A
$N a_{2} [P b (O H)_{2}]$ , $P b C r O_{4}$ and $(N H_{4})_{2} [P b (C H_{3} C O O)_{4}]$
B
$P b C r O_{4}$ , $N a_{2} [P b (O H)_{4}]$ and $[P b (N H_{3})_{4}] S O_{4}$
C
$N a_{2} [P b (O H)_{2}]$ , $P b C r O_{4}$ and $[P b (N H_{3})_{4}] S O_{4}$
D
$P b C r O_{4}$ , $N a_{2} [P b (O H)_{4}]$ and $(N H_{4})_{2} [P b (C H_{3} C O O)_{4}]$

Solution

$P b C l_{2} + K_{2} C r O_{4} \to P b C r O_{4} (A) + 2 K C l$

$P b C r O_{4} + 4 N a O H \to N a_{2} [P b (O H)_{4}] (B) + N a_{2} C r O_{4}$

$P b S O_{4} + 4 C H_{3} C O O N H_{4} \to (N H_{4})_{2} [P b (C H_{3} C O O)_{4}] (X) + (N H_{4})_{2} S O_{4}$

Concept behind this question

Concept-wise practice with instant solutions on Fundamenthol.