JEE Main 2026 — Jan 21, Shift 2 — Chemistry solution

JEE Main2026Jan 21, Shift 2Chemistry

Aqueous HCl reacts with $M n O_{2} (s)$ to form $M n C l_{2} (a q)$ , $C l_{2} (g)$ and $H_{2} O (l)$ . What is the weight (in g) of $C l_{2}$ liberated when 8.7 g of $M n O_{2} (s)$ is reacted with excess aqueous HCl solution ? (Given Molar mass in g mol $^{- 1}$ Mn = 55, Cl = 35.5, O = 16, H = 1)

A
7.1
B
71
C
21.3
D
14.2

Solution

Balanced equation: $M n O_{2} + 4 H C l \to M n C l_{2} + C l_{2} + 2 H_{2} O$ . Stoichiometry: 1 mol $M n O_{2}$ gives 1 mol $C l_{2}$ .

Molar mass of $M n O_{2} = 55 + 32 = 87$ g/mol, so moles of $M n O_{2} = \frac{8.7}{87} = 0.1$ mol. Moles of $C l_{2} = 0.1$ .

Mass of $C l_{2} = 0.1 \times 71 = 7.1$ g.

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