JEE Main 2026 — Jan 23, Shift 1 — Physics solution

JEE Main2026Jan 23, Shift 1Physics

In a screw gauge, the zero of the circular scale lies 3 divisions above the horizontal pitch line when their metallic studs are brought in contact. Using this instrument thickness of a sheet is measured. If pitch scale reading is $1 mm$ and the circular scale reading is $51$ then the correct thickness of the sheet is ______ mm. [Assume least count is $0.01 mm$ ]

A
$1.50$
B
$1.48$
C
$1.54$
D
$1.51$

Solution

With the zero of the circular scale above the horizontal pitch line at contact, the instrument under-reads by 3 divisions — i.e. the zero error is negative.

Zero error $e = - 3 \times 0.01 = - 0.03 mm$ .

Observed reading $= 1 mm + 51 \times 0.01 mm = 1.51 mm$ .

Corrected reading $=$ observed reading $-$ zero error $= 1.51 - (- 0.03) = 1.54 mm$ .

← Back to full paper

Practice more Physics

Concept-wise practice with instant solutions on Fundamenthol.

Start practicing →