JEE Main 2026 Jan 24 Shift 1, Physics Q22: Kinetic Theory of an Ideal Gases

NTA interprets “double its temperature” as doubling the Celsius value, i.e. from $50^{\circ }$C to $100^{\circ }$C (= 373 K).

For a fixed mass at constant volume, $P\propto T$ (in Kelvin):

$\frac{P_f}{P_i}=\frac{T_f}{T_i}\Rightarrow \frac{P_f}{3.23\text{kPa}}=\frac{373}{323}$.

$P_f=3.23\times \frac{373}{323}=3.73$ kPa $=3730$ Pa.

Note: A stricter reading would double the absolute temperature ($323\to 646$ K), giving $P_f=6460$ Pa. The NTA-accepted answer follows the Celsius doubling.