JEE Main 2026 — Jan 28, Shift 2 — Physics solution

JEE Main2026Jan 28, Shift 2Physics

Match List-I with List-II.

Choose the correct answer from the options given below :

A
A-I, B-II, C-IV, D-III
B
A-IV, B-III, C-I, D-II
C
A-I, B-III, C-II, D-IV
D
A-IV, B-I, C-II, D-III

Solution

A. Coefficient of viscosity: $η = \frac{F \cdot d r}{A \cdot d v} = \frac{[ M L T ^{- 2} ] [ L ]}{[ L ^{2} ] [ L T ^{- 1} ]} = [M L^{- 1} T^{- 1}]$ — IV.

B. Surface tension: $S = \frac{F}{L} = \frac{[ M L T ^{- 2} ]}{[ L ]} = [M T^{- 2}] = [M L^{0} T^{- 2}]$ — III.

C. Pressure: $P = \frac{F}{A} = \frac{[ M L T ^{- 2} ]}{[ L ^{2} ]} = [M L^{- 1} T^{- 2}]$ — I.

D. Surface energy: $E = S \times A = [M T^{- 2}] [L^{2}] = [M L^{2} T^{- 2}]$ — II.

A-IV, B-III, C-I, D-II.

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