NEET 2019 — Paper 2019 — Physics solution | Fundamenthol

NEET2019Paper 2019Physics

Q.

The displacement of a particle executing simple harmonic motion is given by

y = A₀ + Asin $ω$ t + Bcos $ω$ t

Then the amplitude of its oscillation is given by :

A
$A_{0} + A^{2} + B^{2}$
B
$A^{2} + B^{2}$
C
$A_{0}^{2} + (A + B)^{2}$
D
$A + B$

Solution

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