NEET 2024, Physics Q9: Simple Harmonic Motion And Oscillation

NEET2024Physics

If $x = 5 sin (π t + \frac{π}{3})$ m represents the motion of a particle executing simple harmonic motion, the amplitude and time period of motion, respectively, are:

A
5 cm, 1 s
B
5 m, 1 s
C
5 cm, 2 s
D
5 m, 2 s

Solution

Compare with $x = A sin (ω t + ϕ)$ : amplitude $A = 5$ m, angular frequency $ω = π$ rad/s.

Time period $T = \frac{2 π}{ω} = \frac{2 π}{π} = 2$ s.

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NEET 2024, Physics Q9: Simple Harmonic Motion And Oscillation

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