NEET 2022 — Physics solution

NEET2022Physics

The energy that will be ideally radiated by a 100 kW transmitter in 1 hour is :

Solution

Energy radiated $E = P \times t$ with $P = 100$ kW $= 1 0^{5}$ W and $t = 1$ hr $= 3600$ s.

$E = 1 0^{5} \times 3600 = 3.6 \times 1 0^{8} = 36 \times 1 0^{7}$ J.

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