NEET 2023 — Physics solution

NEET2023Physics

A bullet is fired from a gun at the speed of $280$ ms $^{- 1}$ in the direction $3 0^{\circ}$ above the horizontal. The maximum height attained by the bullet is $(g = 9.8$ ms $^{- 2}$ , $sin 3 0^{\circ} = 0.5)$ :

A
$2000$ m
B
$1000$ m
C
$3000$ m
D
$2800$ m

Solution

For projectile motion, $H_{ma x} = \frac{u ^{2} sin ^{2} θ}{2 g}$ .

$H_{ma x} = \frac{( 280 ) ^{2} \times ( 0.5 ) ^{2}}{2 \times 9.8} = \frac{78400 \times 0.25}{19.6} = 1000$ m.

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