NEET 2023 — Physics solution

NEET2023Physics

A wire carrying a current $I$ along the positive x-axis has length $L$ . It is kept in a magnetic field $B = (2 \hat{i} + 3 \hat{j} - 4 \hat{k})$ T. The magnitude of the magnetic force acting on the wire is:

A
$5 I L$
B
$5 I L$
C
$3 I L$
D
$3 I L$

Solution

$F = I L \times B$ with $L = L \hat{i}$ .

$F = I L \hat{i} \times (2 \hat{i} + 3 \hat{j} - 4 \hat{k}) = I L (3 \hat{k} + 4 \hat{j}) = I L (4 \hat{j} + 3 \hat{k})$ .

$∣ F ∣ = I L 4^{2} + 3^{2} = 5 I L$ .

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