NEET 2024 — Physics solution

NEET2024Physics

$_{82}^{290} X α Y e^{+} Z β^{-} P e^{-} Q$

In the nuclear emission stated above, the mass number and atomic number of the product $Q$ respectively, are:

Solution

Track changes to $(A, Z)$ at each step starting from $(290, 82)$ :

$α$ emission: $A$ decreases by 4, $Z$ by 2 $\Rightarrow (286, 80)$ .

$e^{+}$ (positron) emission: $A$ unchanged, $Z$ decreases by 1 $\Rightarrow (286, 79)$ .

$β^{-}$ emission: $A$ unchanged, $Z$ increases by 1 $\Rightarrow (286, 80)$ .

$e^{-}$ (electron capture or $β^{-}$ ... here interpreted as $β^{-}$ emission per the printed key): $Z$ increases by 1 $\Rightarrow (286, 81)$ .

$∴ Q$ has mass number 286 and atomic number 81.

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