NEET 2024 — Chemistry solution

NEET2024Chemistry

Match List - I with List - II:

List - I (Conversion)	List-II (Number of Faraday required)
A. 1 mol of H $_{2}$ O to O $_{2}$	I. 3F
B. 1 mol of MnO $_{4}^{-}$ to Mn $^{2 +}$	II. 2F
C. 1.5 mol of Ca from molten CaCl $_{2}$	III. 1F
D. 1 mol of FeO to Fe $_{2}$ O $_{3}$	IV. 5F

Choose the correct answer from the options given below:

Solution

(A) H $_{2}$ O $\to \frac{1}{2}$ O $_{2}$ + 2H $^{+}$ + 2e $^{-}$ : 2F per mole of H $_{2}$ O $\Rightarrow$ II.

(B) MnO $_{4}^{-}$ ( $+ 7$ ) $\to$ Mn $^{2 +}$ ( $+ 2$ ) needs 5e $^{-}$ : 5F $\Rightarrow$ IV.

(D) Fe(+2) to Fe(+3) needs 1e $^{-}$ per Fe; 1 mol FeO $\to$ 1F $\Rightarrow$ III.

Match: A-II, B-IV, C-I, D-III.

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