NEET 2024 — Chemistry solution

NEET2024Chemistry

A compound X contains 32 % of A, 20% of B $_{2}$ and remaining percentage of C. Then, the empirical formula of X is: (Given atomic masses of A = 64; B = 40; C = 32)

A
AB $_{2}$ C $_{2}$
B
ABC $_{4}$
C
A $_{2}$ BC $_{2}$
D
ABC $_{3}$

Solution

Take 100 g: A = 32 g, B $_{2}$ = 20 g (so B atoms = 20 g), C = 48 g.

Moles: A $= 32/64 = 0.5$ ; B $= 20/40 = 0.5$ ; C $= 48/32 = 1.5$ .

Divide by smallest 0.5: A:B:C $= 1 : 1 : 3$ , so empirical formula is ABC $_{3}$ .

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