NEET 2025 — Chemistry solution

NEET2025Chemistry

Consider the following compounds: KO $_{2}$ , H $_{2}$ O $_{2}$ and H $_{2}$ SO $_{4}$ .

The oxidation states of the underlined elements in them are, respectively,

Solution

KO $_{2}$ (potassium superoxide): K is an alkali metal — always +1 in compounds. (The two oxygens share a $- 1$ overall charge per O on average.)

H $_{2}$ O $_{2}$ (hydrogen peroxide): $2 (+ 1) + 2 x = 0$ ⇒ $x = - 1$ for O.

H $_{2}$ SO $_{4}$ : $2 (+ 1) + x + 4 (- 2) = 0$ ⇒ $x = + 6$ for S.

$∴$ +1, $-$ 1, +6.

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