NEET 2026 — Chemistry solution

NEET2026Chemistry

Match List I with List II :

List I (Complex/ion)	List II (Shape/geometry)
A. $[P t (C l_{2}) (N H_{3})_{2}]$	I. Octahedral
B. $[C o (N H_{3})_{6}] C l_{3}$	II. Trigonal bipyramidal
C. $[N i C l_{4}]^{2 -}$	III. Square planar
D. $[F e (C O)_{5}]$	IV. Tetrahedral

Choose the correct answer from the options given below :

A
A-I, B-III, C-IV, D-II
B
A-III, B-IV, C-I, D-II
C
A-III, B-I, C-IV, D-II
D
A-IV, B-I, C-III, D-II

Solution

(A) $[P t (C l_{2}) (N H_{3})_{2}]$ : Coordination number 4, Pt $^{2 +}$ is 5d $^{8}$ with strong-field ligands, so dsp $^{2}$ hybridisation → square planar.

(B) $[C o (N H_{3})_{6}] C l_{3}$ : Coordination number 6, d $^{2}$ sp $^{3}$ hybridisation → octahedral.

(C) $[N i C l_{4}]^{2 -}$ : Coordination number 4, Cl $^{-}$ is a weak-field ligand, so no pairing and sp $^{3}$ hybridisation → tetrahedral.

(D) $[F e (C O)_{5}]$ : Coordination number 5, dsp $^{3}$ hybridisation → trigonal bipyramidal.

Hence A-III, B-I, C-IV, D-II.

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