NEET 2026 — Chemistry solution

NEET2026Chemistry

Match List-I with List-II :

Choose the correct answer from the options given below :

Solution

C $_{2}$ H $_{4}$ (ethylene): 4 C–H + 1 C–C $σ$ bonds = 5 $σ$ and 1 $π$ → IV.

C $_{2}$ H $_{2}$ (acetylene): 2 C–H + 1 C–C $σ$ bonds = 3 $σ$ and 2 $π$ → I.

CH $_{4}$ : 4 C–H $σ$ bonds → III.

NH $_{3}$ : 3 N–H $σ$ bonds with 1 lone pair on N → II.

So A-IV, B-I, C-III, D-II.

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