NEET 2026 — Biology solution

NEET2026Biology

$2 (C_{51} H_{98} O_{6}) + 145 O_{2} \to 102 C O_{2} + 98 H_{2} O$ + energy

The Respiratory Quotient (RQ) of a biomolecule used for respiration, as per the above equation would be :

Solution

The respiratory quotient is defined as

$R Q = \frac{Volume of C O _{2} evolved}{Volume of O _{2} consumed}$

From the given equation, 145 mol of O $_{2}$ is consumed and 102 mol of CO $_{2}$ is evolved, so

$R Q = \frac{102}{145} \approx 0.7$

This value lies between 0.5 and 0.95, which is characteristic of fat respiration.

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