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Introduction And Nomenclature

ChemistryCoordination CompoundsFor NEET aspirants

Coordination compounds are compounds in which a central metal atom or ion is bound to a fixed number of ions or molecules, called ligands, through coordinate bonds, as in and . This page covers Werner's theory, every key term (ligand, denticity, chelate, coordination number, oxidation state) and the IUPAC names of coordination compounds, using the latest NCERT forms such as chlorido and cyanido. Naming and formula questions from this topic appear every year in JEE Main and NEET.

On this page1What they are2Werner's theory3Key terms4Types of ligands5Formulas6IUPAC names7Solved examples
Key Formulas - Quick Reference
  1. ★ Must learn Oxidation state:
  2. ★ Must learn Coordination number = number of donor atoms bonded to the metal (count bonds), not the number of ligands
  3. ★ Must learn Moles of AgCl from 1 mol of complex = number of outside the square bracket
  4. Ions per formula unit = counter ions + 1 complex ion; gives 4 ions
  5. ★ Must learn Name order: cation, then anion; inside the bracket: ligands (A to Z), metal, (oxidation state in Roman numerals)
  6. Anionic ligands: -ide to -ido, -ate to -ato, -ite to -ito (chlorido, sulphato, nitrito)
  7. Neutral ligands keep their names, except aqua (), ammine (), carbonyl (), nitrosyl ()
  8. Prefixes: di, tri, tetra; but bis, tris, tetrakis when the ligand name already has a number, e.g. tris(ethane-1,2-diamine)
  9. ★ Must learn Anionic complex: metal name + -ate (ferrate, cuprate, argentate, aurate, plumbate, stannate)
  10. Chelate effect: a chelating ligand (en, ox, EDTA) gives a far more stable complex than the same number of unidentate donors

1. What Are Coordination Compounds?

Transition metals have a strong tendency to hold neutral molecules or anions around themselves. The compounds formed this way are called coordination compounds, and they are everywhere. Chlorophyll, the green pigment of plants, is a complex of Mg. Haemoglobin, the oxygen carrier in blood, is a complex of Fe. Vitamin is a complex of Co.

One of the earliest known coordination compounds, Prussian blue, was made by accident in 1704 by Diesbach, a colour maker in Berlin. Today these compounds are important in metallurgy, analytical chemistry, medicine and industrial catalysis (for example, polymerisation).

Coordination compound: a compound in which a central metal atom or ion is linked to a fixed number of ions or neutral molecules (ligands) by coordinate bonds, for example . The bracketed unit is the coordination entity. When the entity carries a charge (positive or negative) it is called a complex ion.
Anatomy of the coordination compound hexaamminecobalt(III) chloride The complex ion [Co(NH3)6]3+ drawn as an octahedron: a central cobalt(III) ion bonded to six ammonia ligands through their nitrogen donor atoms, enclosed in square brackets as the coordination sphere. Three chloride counter ions sit outside the bracket in the ionisation sphere. Coordination number 6, oxidation state +3. NH3 Co NH3 NH3 NH3 NH3 NH3 3+ Cl− Cl− Cl− donor atom: N of NH3 ligand NH3 (lone-pair donor) counter ions: 3 Cl− (ionisation sphere) central metal ion Co3+ coordination sphere [ ] coordination number = 6 oxidation state of Co = +3 polyhedron: octahedral
Figure 1: Anatomy of : everything inside the brackets stays together in water; only the three outside are free ions.

Figure 1 shows all the parts at once. The metal ion and the six ligands inside the square bracket move together as one particle. The three chloride ions outside the bracket are ordinary ions that separate in water.

1.1 Molecular (Addition) Compounds

When solutions containing two or more stable compounds in simple molar ratios are evaporated, crystals of new substances form. These are called molecular or addition compounds:

Addition compounds fall into two groups: those that lose their identity in solution (double salts) and those that keep it (coordination compounds). The last three compounds above are really , and .

1.2 Double Salts vs Coordination Compounds

Double salts (lattice compounds) are stable only in the solid state. In water they break up completely into their simple ions. An aqueous solution of carnallite shows the properties of , and ions; potash alum shows those of , and ions. Mohr's salt behaves the same way:

Coordination compounds behave very differently. In water they give complex ions that stay whole: copper(II) sulphate with ammonia gives the deep blue ion, and potassium ferrocyanide gives the ion. The ferrocyanide solution gives no test for or ions.

Double salt versus coordination compound in water Two lanes. Mohr's salt, a double salt, dissolves in water to give free iron(II), ammonium and sulphate ions, so it gives the test for iron(II). Potassium ferrocyanide, a coordination compound, gives four potassium ions and the intact hexacyanidoferrate(II) ion, so it gives no test for free iron(II) or cyanide ions. Double salt: breaks into all its simple ions Mohr's salt FeSO4·(NH4)2SO4·6H2O water Fe2+ 2NH4+ 2SO42– ✓ Fe2+ test positive: free Fe2+ is present Coordination compound: the complex ion stays whole Potassium ferrocyanide K4[Fe(CN)6] water 4K+ [Fe(CN)6]4– ✗ Fe2+ test negative, ✗ CN– test negative Fe2+ and CN– are locked inside the complex ion Both give 5 ions per formula unit, but only the double salt releases Fe2+.
Figure 2: A double salt loses its identity in water; a coordination compound keeps its complex ion intact.
FeatureDouble saltCoordination compound
Exists assolid (crystal) onlysolid and in solution
In waterbreaks into all simple ionscomplex ion stays intact
Ion testsgives the test of every ionno test for the metal ion or ligand inside the bracket
Examplescarnallite, potash alum, Mohr's salt, ,

Perfect and imperfect complexes. Complex ions differ in how far they dissociate. In a perfect complex such as the complex ion is so stable that it hardly dissociates, so no tests for or are seen:

In an imperfect complex such as the complex ion dissociates reversibly to an appreciable extent, so it gives the tests of its simple ions:

A very unstable imperfect complex dissociates completely and then behaves like a double salt.

2. Werner's Coordination Theory

Alfred Werner, a Swiss chemist often called the father of coordination chemistry, proposed his theory in 1893 after studying compounds such as and . He received the Nobel Prize in 1913. His main postulates are:

  1. In a coordination compound the metal shows two kinds of valency: primary (ionisable) and secondary (non-ionisable).
  2. Primary valency equals the oxidation state of the metal. It is satisfied only by anions, it can change from compound to compound and it is non-directional. Werner drew it as a dotted line.
  3. Secondary valency equals the coordination number. It is fixed for a given metal ion and is satisfied by neutral molecules or anions that carry a lone pair. Werner drew it as a thick line.
  4. Every metal ion tries to satisfy both valencies. An anion inside the coordination sphere can satisfy a primary and a secondary valency at the same time (like one in ).
  5. Ions attached by primary valency ionise in solution; groups attached by secondary valency do not.
  6. Secondary valencies are directed in space: six point to the corners of an octahedron, four to the corners of a square or a tetrahedron. This fixed geometry is what makes stereoisomerism possible.

Werner tested his idea with silver nitrate, which precipitates only free chloride ions, and with conductivity, which counts the ions in solution. In all three chlorides precipitate at once, so all three are outside the coordination sphere and the compound is :

Werner's silver nitrate experiment on cobalt(III) chloride ammoniates Four cobalt chloride ammonia compounds with their colours: yellow CoCl3.6NH3 gives three moles of silver chloride, purple CoCl3.5NH3 gives two, and the green and violet forms of CoCl3.4NH3 give one each. Werner explained this with the formulas hexaamminecobalt(III) chloride, pentaamminechloridocobalt(III) chloride and the trans and cis tetraamminedichloridocobalt(III) chlorides. Compound and colour AgCl precipitated Werner's formula in water CoCl3·6NH3 yellow AgCl AgCl AgCl [Co(NH3)6]Cl3 4 ions CoCl3·5NH3 purple AgCl AgCl [CoCl(NH3)5]Cl2 3 ions CoCl3·4NH3 green AgCl trans-[CoCl2(NH3)4]Cl 2 ions CoCl3·4NH3 violet AgCl cis-[CoCl2(NH3)4]Cl 2 ions + AgNO3 Only Cl– outside the bracket precipitates; Cl inside is bonded to Co
Figure 3: Werner's key evidence: the moles of AgCl and the number of ions in solution reveal which chlorides are outside the coordination sphere.

In each compound, cobalt shows a primary valency of 3 and a secondary valency of 6. As ammonia molecules are removed, chloride ions move inside the bracket to keep the coordination number at 6, so fewer chlorides precipitate and fewer ions are present. Werner also noticed that exists in two forms (green and violet). He explained them as the trans and cis arrangements of the same octahedral ion, which strongly supported his octahedral model (see Isomerism).

Werner's primary and secondary valencies in two cobalt ammine chlorides Werner's picture: thick lines are the six secondary valencies (the coordination number) that fix the octahedron; dotted lines are the three primary valencies (the oxidation state) satisfied by chloride. In CoCl3.6NH3 all three chlorides are ionisable. In CoCl3.5NH3 one chloride is bonded to cobalt and satisfies a primary and a secondary valency at the same time. Cl− Cl− Cl− NH3 NH3 NH3 NH3 NH3 NH3 Co Cl− Cl− Cl NH3 NH3 NH3 NH3 NH3 Co CoCl3·6NH3 = [Co(NH3)6]Cl3 3 primary valencies by free Cl− CoCl3·5NH3 = [CoCl(NH3)5]Cl2 one Cl satisfies both valencies secondary valency = CN 6 (non-ionisable) primary valency = +3 (ionisable)
Figure 4: Werner's own notation. Thick lines (secondary valency) never ionise; dotted lines (primary valency) to free ions do, which is why gives only 2 mol AgCl.
Exam Trick

Outside the bracket = in the beaker. Only the ions written outside the square bracket are free in water. Count them to get the moles of AgCl, the moles of , the number of ions and the conductivity order in one step.

Limitations of Werner's theory. It could not explain (i) why only certain elements form coordination compounds, (ii) why the bonds are directional, (iii) the magnetic properties and (iv) the colour of complexes. Valence bond theory and crystal field theory (see Bonding) answer these questions.

Key idea
Werner: primary valency = oxidation state (ionisable, satisfied by anions); secondary valency = coordination number (fixed, non-ionisable and pointing in fixed directions).

3. Important Terms

3.1 Coordination Entity and Central Atom

The coordination entity is the central atom or ion together with the ligands bonded to it. It can be a cation (), an anion () or neutral (, ).

The central atom or ion is the atom to which a fixed number of ligands are attached in a definite geometry. It accepts electron pairs, so it acts as a Lewis acid and must have empty orbitals. This is why transition metals, with vacant d orbitals, form complexes so readily. In and the central ions are and ; in it is a neutral Ni atom.

3.2 Ligands and Donor Atoms

A ligand is an ion or molecule that donates a pair of electrons to the central atom through a coordinate (dative) bond, so it acts as a Lewis base. Ligands are usually polar molecules such as and , or anions such as , and , each with at least one lone pair. The atom of the ligand that actually forms the bond is the donor atom (N in , O in , C in ). A few cations can act as ligands if they still carry a lone pair, for example and the hydrazinium ion .

3.3 Coordination Number

The coordination number (CN) is the number of donor atoms directly bonded to the central atom, which equals the number of coordinate bonds. Only bonds are counted; any bonds between ligand and metal are ignored. A hexadentate ligand counts as six bonds, not one. The most common values are 2, 4 and 6; lighter transition metals usually show 4 or 6, while heavier metals can show 8 or more.

ComplexLigandsDonor atomsCN
2 2 N2
4 4 C4
6 6 Cl6
3 en (bidentate)6 N6
1 EDTA (hexadentate)2 N + 4 O6
8 8 C8

3.4 Coordination Sphere and Counter Ions

The central atom and the ligands directly attached to it form the coordination sphere, written inside square brackets. It behaves as a single unit, and the groups inside it do not ionise. The ions written outside the bracket form the ionisation sphere; they are called counter ions and they do ionise. In the coordination sphere is and the counter ions are four ions.

3.5 Coordination Polyhedron

The spatial arrangement of the donor atoms around the central atom is the coordination polyhedron. The common ones are octahedral (), square planar (), tetrahedral () and linear (). Why a complex takes a particular shape is explained in Bonding.

Common coordination polyhedra with example complexes Five cards: linear [Ag(NH3)2]+ for coordination number 2, tetrahedral [Ni(CO)4] and square planar [Ni(CN)4]2- for coordination number 4, trigonal bipyramidal [Fe(CO)5] for 5 and octahedral [Co(NH3)6]3+ for 6, each with its bond angle. CN 2: linear Ag NH3 NH3 [Ag(NH3)2]+ bond angle 180° CN 4: tetrahedral CO CO Ni CO CO [Ni(CO)4] bond angle 109.5° CN 4: square planar CN Ni CN CN CN [Ni(CN)4]2− bond angle 90° CN 5: trigonal bipyramidal CO CO Fe CO CO CO [Fe(CO)5] bond angle 90°, 120° CN 6: octahedral NH3 Co NH3 NH3 NH3 NH3 NH3 [Co(NH3)6]3+ bond angle 90°
Figure 5: The coordination polyhedron is the shape traced by the donor atoms. Coordination number 4 has two possible shapes, tetrahedral and square planar.

3.6 Oxidation Number of the Central Atom

The oxidation number is the charge the central atom would carry if all the ligands were removed together with the electron pairs they share with it. Neutral ligands (, , , en) count as 0. For :

Similarly the oxidation number of Fe in is +2, of Co in is +3 and of Ni in is 0. The charge on a complex is the sum of the charges of its parts.

Flowchart: finding the oxidation number of the central metal Flowchart: write the complex and its charge, let counter ions fix the charge of the coordination entity, count neutral ligands as zero and anionic ligands as minus one or minus two, then solve for the metal. Worked notes: iron is plus three in potassium trioxalatoferrate(III) and nickel is zero in tetracarbonylnickel(0). example example Write the complex with its charge Counter ions fix the bracket's charge: K3[...] means [...]3− Neutral ligands count 0: H2O, NH3, CO, NO, en, py Anionic ligands: Cl−, CN−, NO2− = −1; C2O42−, SO42−, CO32− = −2 Solve: x + (sum of ligand charges) = charge on the bracket x = oxidation state, in Roman numerals K3[Fe(C2O4)3]: bracket = −3, 3 × (−2) = −6, x = +3: iron(III) [Ni(CO)4]: x + 0 = 0, nickel(0)
Figure 6: Five steps give the oxidation state of any central atom. Neutral ligands add nothing, so only the anionic ligands and the overall charge matter.

3.7 Homoleptic and Heteroleptic Complexes

A complex with only one kind of ligand is homoleptic (). A complex with more than one kind of ligand is heteroleptic ().

Quick Recall: tap to check
What is the coordination number of Fe in ?
6: three bidentate oxalate ions give six O donor atoms. Iron is +3.
How many moles of AgCl does 1 mol of give?
2 mol: only the two chlorides outside the bracket are free ions.
Why can never act as a ligand?
Its nitrogen has no lone pair left to donate.
Key idea
A complex is a Lewis acid-base adduct: the metal accepts electron pairs, the ligands donate them, and everything inside the square bracket moves as one unit.

4. Types of Ligands

4.1 By Number of Donor Atoms (Denticity)

The denticity of a ligand is the number of donor atoms it uses to bind one metal ion. Ligands with one donor atom are unidentate; those with two or more are polydentate.

TypeDonor atomsExamples
Unidentate1, , , , , , , , pyridine (py)
Bidentate2ethane-1,2-diamine (en, N and N), oxalate (ox, O and O), glycinate (gly, N and O), carbonate, 2,2′-bipyridyl (bpy or dipy), 1,10-phenanthroline (phen)
Tridentate3diethylenetriamine (dien), 2,2′,2″-terpyridine (terpy)
Tetradentate4triethylenetetramine (trien), nitrilotriacetate ()
Pentadentate5ethylenediaminetriacetate ion
Hexadentate6ethylenediaminetetraacetate, (2 N + 4 O)
Ligands classified by denticity, with donor atoms highlighted Gallery of ligands. Unidentate: ammonia, water, chloride, cyanide, carbon monoxide, pyridine. Bidentate: ethane-1,2-diamine with two nitrogen donors, oxalate with two oxygen donors, glycinate with one nitrogen and one oxygen donor. Tridentate: diethylenetriamine with three nitrogen donors. Hexadentate: EDTA with two nitrogen and four oxygen donors. Ambidentate: nitrite binding through nitrogen or oxygen, and thiocyanate binding through sulphur or nitrogen. UNIDENTATE NH3 H2O Cl– CN– CO py one donor atom BIDENTATE: en H2N NH2 ethane-1,2-diamine BIDENTATE: ox2– O O O O − − oxalate BIDENTATE: gly– H2N O O − glycinate TRIDENTATE: dien H2N N H NH2 diethylenetriamine HEXADENTATE: EDTA4– O O N O O N O O O O − − − − ethylenediaminetetraacetate: 2 N + 4 O donors AMBIDENTATE: NO2– AMBIDENTATE: SCN– M N O O– nitrito-N M O– N O nitrito-O M S– C N thiocyanato-S M N– C S thiocyanato-N
Figure 7: Denticity = number of donor atoms (shaded) a ligand can use at once. Ambidentate ligands have two possible donor atoms but use only one at a time.

4.2 Chelating Ligands and the Chelate Effect

A polydentate ligand whose shape lets two or more of its donor atoms bind the same metal ion at once closes one or more rings. It is called a chelating ligand, the ring compound formed is a chelate, and the process is chelation. In each ethane-1,2-diamine closes a five-membered Cu-N-C-C-N ring.

Chelate rings in bis(ethane-1,2-diamine)copper(II) and the chelate effect Two ethane-1,2-diamine ligands each close a five-membered ring of copper, nitrogen, carbon, carbon and nitrogen. A bar chart compares log beta: 8.6 for hexaamminenickel(II) and 18.3 for tris(ethane-1,2-diamine)nickel(II). Replacing six ammonia by three en raises the particle count from 4 to 7, so entropy favours the chelate. N H2 N H2 CH2 CH2 N H2 N H2 H2C H2C Cu 2+ Chelate: [Cu(en)2]2+ two 5-membered Cu-N-C-C-N rings (shaded) CHELATE EFFECT (log β) [Ni(NH3)6]2+ 8.6 [Ni(en)3]2+ 18.3 [Ni(NH3)6]2+ + 3en → [Ni(en)3]2+ + 6NH3 4 particles → 7 particles entropy rises, so the chelate wins
Figure 8: Chelation closes rings around the metal; the chelate is about times more stable than .

Chelate complexes are much more stable than similar complexes of unidentate ligands. This extra stability is called the chelate effect. The main reason is entropy: when three en molecules replace six molecules, the number of free particles rises from 4 to 7, so the change is strongly favoured:

  • Ring size matters. Chelates with 5- or 6-membered rings are the most stable; smaller rings are strained.
  • 5-membered rings are most stable with saturated ligands such as en.
  • 6-membered rings are most stable with unsaturated ligands that have conjugated double bonds (such as acetylacetonate), because resonance involving the metal d orbitals and the ligand p orbitals adds stability.
Exam Trick

Coordination number counts teeth, not ligands. Think of denticity as the number of teeth a ligand bites with: en has 2 teeth, ox has 2, EDTA has 6. So has 3 ligands but CN = 3 × 2 = 6.

4.3 Flexidentate Ligands

A polydentate ligand does not always use all its donor atoms. Such ligands are called flexidentate. EDTA is normally hexadentate but can act as a penta- or tetradentate ligand with some metal ions. Sulphate and carbonate can bind through one O atom (unidentate) or two (bidentate).

4.4 Ambidentate Ligands

An ambidentate ligand has two different donor atoms but binds the metal through only one of them at a time (Figure 7, bottom row). The donor atom is shown in the name:

LigandBinds throughName as ligandOlder name
N (M-)nitrito-Nnitro
O (M-ONO)nitrito-Onitrito
S (M-SCN)thiocyanato-Sthiocyanato
N (M-NCS)thiocyanato-Nisothiocyanato
C (M-CN) or N (M-NC)cyanido / isocyanidocyano / isocyano

Because the same ligand can bind in two ways, ambidentate ligands give linkage isomers (see Isomerism). Do not confuse them with bidentate ligands: en uses both its N atoms together, while uses either S or N.

Bidentate (en)Uses both donor atoms at the same time, closes a chelate ring and adds 2 to the coordination number.
Ambidentate (thiocyanate)Has two possible donor atoms (S or N) but uses only one at a time, so it gives linkage isomers.
Key idea
Coordination number counts donor atoms, not ligands: three en ligands give CN = 6.

5. Writing the Formula of a Complex

The formula is a short-hand description of the composition. IUPAC (and NCERT) use these rules:

  1. Write the central atom first.
  2. Then list the ligands in alphabetical order of their formulas or abbreviations; the charge of a ligand does not affect its position ( before before ).
  3. Put polyatomic ligands and abbreviations in round brackets: (), (en), (CN).
  4. Enclose the whole coordination entity in square brackets, with no spaces between the ligands and the metal.
  5. Write the charge of a complex ion as a right superscript outside the bracket: .
  6. In a salt, write the cation first: , .

Example: tetraamminedichloridocobalt(III) ion is written . The order of ligands in a formula is sometimes relaxed in textbooks; it never changes the compound. In a name, however, the alphabetical order is strict.

6. IUPAC Nomenclature of Coordination Compounds

Many complexes still have trivial names (ferrocyanide, Zeise's salt, cisplatin), so IUPAC set up one system that works for all of them. The names below follow the current NCERT book, which uses the 2005 IUPAC rules (chlorido, cyanido). Older forms (chloro, cyano) are shown alongside because they still appear in exam options.

6.1 Rule 1: Cation Before Anion

Whether the complex is the cation or the anion, always name the cation first and then the anion, as in simple salts (sodium chloride).

  • : hexaamminecobalt(III) chloride (complex cation)
  • : potassium hexacyanidoferrate(II) (complex anion)
  • : tetraammineplatinum(II) tetrachloridoplatinate(II) (both complex)
  • : tetracarbonylnickel(0) (neutral complex, written as one word)

6.2 Rule 2: Ligands First, Then the Metal

Inside the coordination entity, name the ligands first, in alphabetical order, and then the central atom, all as one word. Ligand names follow three patterns.

(a) Anionic ligands end in -o: -ide becomes -ido, -ate becomes -ato and -ite becomes -ito.

AnionLigand name (older name)AnionLigand name
fluorido (fluoro)amido
chlorido (chloro)carbonato
bromido (bromo)oxalato
iodido (iodo)sulphato
hydridosulphito
oxido (oxo)thiosulphato
hydroxido (hydroxo)nitrato
peroxido (peroxo)nitrito-N or nitrito-O
cyanido (cyano)thiocyanato-S or thiocyanato-N
sulphido (thio)acetato
nitridoethylenediaminetetraacetato

(b) Neutral ligands keep the name of the molecule. The exceptions (in bold) are aqua, ammine, carbonyl and nitrosyl, plus thiocarbonyl for .

LigandName as ligandLigandName as ligand
aquadioxygen
ammine (double m)dinitrogen
carbonylenethane-1,2-diamine (older: ethylenediamine)
nitrosylpypyridine
thiocarbonyltriphenylphosphine
methylamine (organic amine: single m)ethene

(c) Cationic ligands end in -ium: hydrazinium (). The older name nitrosylium was used for ; today it is simply called nitrosyl. A cation can be a ligand only if it still has a lone pair, so never acts as a ligand.

6.3 Rule 3: Numerical Prefixes

Use di, tri, tetra, penta, hexa to show how many of each simple ligand are present (tetraammine, dichlorido, trioxalato). If the ligand name already contains a number (ethane-1,2-diamine) or is a long substituted name (triphenylphosphine), use bis, tris, tetrakis, pentakis and put the ligand name in brackets: tris(ethane-1,2-diamine), bis(triphenylphosphine). Being polydentate does not decide it: oxalate is bidentate but takes tri (trioxalato).

Alphabetical order ignores these prefixes. Tetraammine is alphabetised under "a" and dichlorido under "c", so the correct name of is tetraamminedichloridocobalt(III), never dichloridotetraamminecobalt(III).

6.4 Rule 4: Naming the Metal

In a cationic or neutral complex the metal keeps its usual name (cobalt, nickel, platinum). In an anionic complex the metal name ends in -ate, and for several metals the Latin root is used:

MetalIn an anionic complexMetalIn an anionic complex
Iron (Fe)ferrateCobalt (Co)cobaltate
Copper (Cu)cuprateNickel (Ni)nickelate
Silver (Ag)argentateZinc (Zn)zincate
Gold (Au)auratePlatinum (Pt)platinate
Lead (Pb)plumbateChromium (Cr)chromate
Tin (Sn)stannateAluminium (Al)aluminate

6.5 Rule 5: Oxidation State

Give the oxidation state of the metal as a Roman numeral in brackets right after the metal name, with no space: cobalt(III), ferrate(II). Use (0) for zero, as in tetracarbonylnickel(0).

6.6 Ambidentate Ligands in Names

Show the donor atom after the ligand name: nitrito-N for M- and nitrito-O for M-ONO; thiocyanato-S for M-SCN and thiocyanato-N for M-NCS (see the table in section 4.4).

IUPAC name builder for coordination compounds Two colour-coded names. Potassium hexacyanidoferrate(II) is split into cation, numerical prefix hexa, ligand cyanido, Latin metal root ferr, anion ending ate and oxidation state two. Tetraamminedichloridocobalt(III) chloride is split into tetra, ammine, di, chlorido, cobalt, oxidation state three and the chloride anion; ammine comes before chlorido because a comes before c. K4[Fe(CN)6] potassium cation hexa 6 × cyanido CN– ligand ferr Fe (Latin) ate anion (II) Fe +2 [CoCl2(NH3)4]Cl tetra 4 × ammine NH3 (a) di 2 × chlorido Cl– (c) cobalt metal (III) Co +3 chloride anion Order: cation → ligands A to Z → metal (+ate if anion) → (oxidation state) → anion
Figure 9: Every IUPAC name is built from the same blocks. Ligands go in alphabetical order of their names (prefixes such as tetra and di are ignored).
Flowchart: naming a coordination compound step by step Naming flowchart: cation before anion; ligands in alphabetical order ignoring multiplying prefixes; bis, tris or tetrakis when the ligand name contains a number or is long, otherwise di, tri, tetra; the metal takes the ending ate with a Latin root only when the complex is an anion; finish with the oxidation state in Roman numerals. yes no yes no Formula of the compound Name the cation first, then the anion Inside [ ]: ligands A to Z (ignore di, tri, bis, tris) Ligand name has a number or is long? bis, tris, tetrakis + name in ( ) di, tri, tetra, penta, hexa Complex is an anion? metal + -ate (Latin root): ferrate, cuprate, argentate usual metal name: cobalt, nickel, platinum Add the oxidation state: (II), (III), (0) Example: K3[Fe(CN)6] = potassium hexacyanidoferrate(III)
Figure 10: Two questions decide every name: does the ligand name need bis/tris, and is the complex an anion (then the metal ends in -ate)?
Exam Trick

"Cation, ABC ligands, Metal, Roman numeral." Say it while you write: cation first; ligands A to Z (prefixes don't vote); metal (+ate only if the complex is an anion); oxidation state in brackets; then the anion. The ending -ate always means the complex is an anion.

JEE Advanced

Bridging ligands (). In a polynuclear complex, a ligand that links two metal atoms is marked with the prefix and separated by hyphens. Example: , where and both bridge the two Co atoms, is named -amido--hydroxidobis[bis(ethane-1,2-diamine)cobalt(III)] sulphate. The older style lists each half: bis(ethylenediamine)cobalt(III)--amido--hydroxobis(ethylenediamine)cobalt(III) sulphate. Check the charge: , balanced by two .

Hapticity (). When a ligand bonds through several adjacent atoms with its electrons, the number of bonded atoms is shown by . Zeise's salt is potassium trichlorido(-ethene)platinate(II), and ferrocene is bis(-cyclopentadienyl)iron(II). Compounds with a metal-carbon bond like these are called organometallic compounds.

Mind map of coordination compounds: Werner's theory, terms, ligands and naming Mind map: Werner's primary and secondary valencies, key terms (central atom, ligand, coordination number, coordination sphere), ligand types by denticity, the chelate effect, formula-writing rules and IUPAC naming rules. Coordination compounds Werner's theory primary valency = oxidation state secondary valency = CN AgCl counts free Cl− secondary valencies are directional Key terms central atom: Lewis acid ligand: Lewis base CN = number of donor atoms [ ] = coordination sphere Ligands unidentate: NH3, Cl− bidentate: en, ox, gly hexadentate: EDTA4− ambidentate: NO2−, SCN− Chelate effect ring closes on the metal 5- and 6-membered rings best entropy: more free particles [Ni(en)3]2+ ≫ [Ni(NH3)6]2+ Formula rules metal first ligands A to Z by symbol charge outside the [ ] cation before anion IUPAC names -ide → -ido, -ate → -ato aqua, ammine, carbonyl anion: metal + -ate Roman numeral for oxidation state
Figure 11: Everything on this page in one picture. Revise it branch by branch before the solved examples.
Quick Recall: tap to check
Name .
Potassium hexacyanidoferrate(III): the complex is an anion, so iron becomes ferrate.
Write the formula of tetraamminedichloridocobalt(III) chloride.
Why is it tris(ethane-1,2-diamine) but trioxalato?
The name ethane-1,2-diamine already contains numbers, so bis/tris are used; oxalato does not.

7. Solved Examples

Solved Example 1
Write the formulas of these coordination compounds: (i) hexaammineiron(III) nitrate; (ii) ammonium tetrachloridocuprate(II); (iii) sodium chloridopentacyanidoferrate(III); (iv) potassium hexafluoridocobaltate(III).
Solution:

Find the charge of each complex from the oxidation state, then balance it with the counter ions.

  • (i) + 6 neutral gives , which needs three :
  • (ii) + 4 gives , which needs two :
  • (iii) + 1 + 5 : , which needs three :
  • (iv) + 6 gives :
Solved Example 2
Write the IUPAC names of: (i) ; (ii) ; (iii) ; (iv) .
Solution:
  • (i) , so Co is +3: pentaamminebromidocobalt(III) sulphate (older: pentaamminebromocobalt(III) sulphate)
  • (ii) Both ions are complexes and their charges must cancel. With the usual +3 state, needs , where gives Cr +3: hexaammineiron(III) hexacyanidochromate(III)
  • (iii) , so Co is +3: pentaamminesulphatocobalt(III) ion
  • (iv) , so Fe is +3; aqua (a) comes before hydroxido (h): pentaaquahydroxidoiron(III) ion
Solved Example 3
Find the oxidation state and coordination number of the metal in (i) ; (ii) ; (iii) (used to treat lead poisoning); (iv) .
Solution:
ComplexOxidation stateDonor atomsCN
, so +33 ox × 2 O6
, so +32 en × 2 N + 2 Cl6
, so +21 EDTA × 6 (2 N + 4 O)6
, so 05 C5

Key point: count donor atoms, not ligands. The EDTA complex has one ligand but CN = 6.

Solved Example 4
One mole of gives two moles of AgCl with excess . Write its structural formula and IUPAC name, and state the number of ions it gives in water and the primary and secondary valencies of cobalt.
Solution:

Two chlorides precipitate, so two are outside the bracket. The third Cl must be inside, bonded to Co, with the five making up CN = 6.

  • Formula: ; name: pentaamminechloridocobalt(III) chloride
  • Ions in water: + 2 = 3 ions (a 1:2 electrolyte)
  • Primary valency = oxidation state = 3; secondary valency = CN = 6. The Cl inside the bracket satisfies one primary and one secondary valency at once.
Solved Example 5
Which compound has the highest molar conductivity in water?
(A)
(B)
(C)
(D)
Solution:

Answer: (D). Conductivity rises with the number of ions per formula unit. The ions are (A) 0, a non-electrolyte that gives no AgCl; (B) 2; (C) 3; (D) 4. So the order is A < B < C < D, and conducts best.

Solved Example 6
Write the IUPAC name of and explain the order of the ligands.
Solution:

Oxidation state: , so Co is +3. The ligand names are ammine, aqua and chlorido. Compare them letter by letter, ignoring the prefix tetra: ammine and aqua both start with "a", and "m" comes before "q", so ammine comes first; chlorido comes last.

Answer: tetraammineaquachloridocobalt(III) chloride. Two common wrong answers are "aquatetraammine..." (sorting by the prefix) and "chloridotetraammine..." (putting anions first).

Solved Example 7
Name (i) ; (ii) ; (iii) .
Solution:
  • (i) Fe: , so +3; the complex is an anion, so iron becomes ferrate. Oxalato has no number inside its name, so the plain prefix tri is used: potassium trioxalatoferrate(III)
  • (ii) Ni: ; ethane-1,2-diamine already contains a number, so tris is used with brackets: tris(ethane-1,2-diamine)nickel(II) chloride
  • (iii) Au: , so +1; anionic gold uses the Latin root: sodium dicyanidoaurate(I)

Key point: tri vs tris depends on the ligand name, not on whether the ligand is bidentate.

Solved Example 8
The compounds (yellow) and (red) have the same formula. Name both and explain the difference.
Solution:

In both, , so Co is +3. Nitrite is ambidentate. In the yellow compound it binds through N; in the red compound it binds through O.

  • : pentaamminenitrito-N-cobalt(III) chloride (older: pentaamminenitrocobalt(III) chloride)
  • : pentaamminenitrito-O-cobalt(III) chloride (older: pentaamminenitritocobalt(III) chloride)

They differ only in the donor atom, so they are linkage isomers.

Solved Example 9
Solutions of Mohr's salt, , and of both contain iron(II), but only one gives the test for . Which one, and why? How many ions does each give per formula unit?
Solution:

Mohr's salt is a double salt; it releases free and gives the test. is a coordination compound; the iron stays locked inside , so there is no test.

  • Mohr's salt: + 2 + 2 = 5 ions
  • : 4 + = 5 ions

Key point: both give 5 ions, so conductivity cannot tell them apart; the chemical test for can.

Solved Example 10
With , which ligand gives the most stable complex?
(A)
(B)
(C) py
(D) en
Solution:

Answer: (D). All of these ligands are neutral N or O donors, but en is bidentate and forms five-membered chelate rings. Replacing six by three en increases the number of free particles from 4 to 7, so entropy favours the chelate. The stability constants show it: for but about 18.3 for , roughly times more stable.

Solved Example 11
The brown ring formed in the test for nitrate is due to . What is the oxidation state of iron?
(A) +1
(B) +2
(C) +3
(D) +4
Solution:

Answer: (A). The complex ion is (one outside). Here nitric oxide is bonded as the nitrosyl cation , which fits the measured magnetic moment (about 3.9 BM, three unpaired electrons):

Name: pentaaquanitrosyliron(I) sulphate. If you treated NO as neutral you would wrongly get +2.

Solved Example 12
A dark green compound has the composition . When its solution is treated with excess , only one-third of the total chlorine precipitates as AgCl. Write its structural formula and name.
Solution:

Total Cl = 3, and one-third of it (1 Cl) is outside the bracket. Cr(III) needs CN = 6, so the other 2 Cl and 4 are coordinated. The remaining 2 are water of crystallisation.

  • Formula:
  • Name: tetraaquadichloridochromium(III) chloride dihydrate
  • Ions in water: 2; moles of AgCl per mole: 1

The violet isomer gives 3 AgCl and the light green isomer gives 2 (hydrate isomers, see Isomerism).

Practice Questions: Write the IUPAC Name
  1. Answer: triamminetriaquachromium(III) chloride
  2. Answer: pentaamminechloridoplatinum(IV) bromide
  3. Answer: dichloridobis(ethane-1,2-diamine)platinum(IV) chloride
  4. Answer: tris(ethane-1,2-diamine)cobalt(III) sulphate
  5. Answer: potassium hexacyanidoferrate(II)
  6. Answer: sodium tetrachloridonickelate(II)
  7. Answer: diamminetetrachloridoplatinum(IV)
  8. Answer: pentacarbonyliron(0)
  9. Answer: ammonium diaquadioxalatonickelate(II)
  10. Answer: diamminesilver(I) dicyanidoargentate(I)
  11. Answer: pentaamminethiocyanato-N-cobalt(III) chloride
  12. Answer: potassium tetraiodidomercurate(II)
  13. Answer: bromidobis(ethane-1,2-diamine)nitrito-O-cobalt(III) ion
  14. Answer: lithium tetrahydridoaluminate(III)
  15. Answer: hexaamminecobalt(III) hexanitrito-O-cobaltate(III)
  16. Answer: ammonium hexathiocyanato-S-platinate(IV)
  17. Answer: triamminetrinitrito-N-cobalt(III)
  18. Answer: sodium hexanitrito-N-cobaltate(III)
  19. Answer: sodium ethylenediaminetetraacetatonickelate(II)
  20. Answer: sodium tetrafluoridooxidochromate(IV)
  21. Answer: pentaamminethiocyanato-N-chromium(III) tetrachloridozincate(II)
  22. Answer: potassium dichloridodioxalatocobaltate(III)
Practice Questions: Write the Formula
  1. potassium trioxalatochromate(III)Answer:
  2. tetrahydroxidozincate(II) ionAnswer:
  3. hexaamminecobalt(III) sulphateAnswer:
  4. pentaamminenitrito-O-cobalt(III) ionAnswer:
  5. tetrabromidocuprate(II) ionAnswer:
Practice Questions: Concept Check
  1. True or false: the coordination number and the oxidation state of a metal mean the same thing.Answer: False. In the oxidation state of Fe is +2 but its coordination number is 6.
  2. A group of atoms can act as a ligand only when it (A) is a small molecule (B) can donate an electron pair (C) is a negative ion (D) is a positive ionAnswer: (B). Neutral molecules and even some cations can be ligands; the lone pair is what matters.
  3. For state what ox stands for, the oxidation number and the coordination number of Cr, and which ligand is didentate.Answer: ox = oxalate; oxidation number +3; CN = 6; oxalate is didentate.
  4. Give the oxidation number of the metal in , , , and .Answer: +3, +2, +3, +3, +3
  5. One mole of gives how many moles of ions in solution, and how many moles of does it need to precipitate all its chloride?Answer: 5 moles of ions (1 complex ion + 4 ); 4 moles of .

Common Mistakes to Avoid

Watch out
  • Writing amine for . The ligand is ammine (double m); a single m is used only for organic amine ligands such as methylamine.
  • Taking the number of ligands as the coordination number. has 3 ligands but 6 donor atoms, so CN = 6.
  • Letting prefixes decide the alphabet. "Dichloridotetraammine..." is wrong: ammine (a) comes before chlorido (c), and di, tri, tetra, bis are ignored.
  • Adding -ate to a cationic or neutral complex ("hexaamminecobaltate"), or forgetting it in an anionic one ("potassium hexacyanidoiron(II)").
  • Using English roots in anions: write ferrate, cuprate, argentate, aurate, plumbate and stannate, not ironate or silverate.
  • Writing the charge of the complex instead of the oxidation state: contains iron(II), not iron(IV).
  • Expecting every chloride to precipitate with . Only outside the square bracket reacts; chlorine inside is bonded to the metal.
  • Using di or tri with ethane-1,2-diamine. The correct forms are bis(ethane-1,2-diamine) and tris(ethane-1,2-diamine), with the ligand name in brackets.
  • Confusing ambidentate with bidentate: has two possible donor atoms but uses one at a time; en uses both of its N atoms at once.

Frequently Asked Questions

What is a coordination compound?

A coordination compound contains a central metal atom or ion bonded to a fixed number of ligands by coordinate bonds, each ligand donating an electron pair. The metal and its ligands form a complex ion or neutral entity, written in square brackets, such as or , which keeps its identity in solution.

What is the difference between a double salt and a coordination compound?

A double salt such as Mohr's salt or potash alum exists only as a solid. In water it breaks completely into simple ions and gives the test for each ion. A coordination compound such as keeps its complex ion intact in water, so the metal ion and the ligands do not give their separate tests.

How do you find the coordination number of a complex?

Count the donor atoms directly bonded to the metal, not the ligands. Each unidentate ligand adds one, each bidentate ligand such as en or oxalate adds two, and EDTA adds six. So has coordination number 6, has 4 and has 2.

Why are chelate complexes more stable than ordinary complexes?

A chelating ligand binds through two or more donor atoms and closes a ring around the metal. Replacing several unidentate ligands by fewer chelating ones releases more free particles, so entropy increases and the stability constant rises sharply. For nickel(II), the en complex is about ten billion times more stable than the ammonia complex.

What is an ambidentate ligand?

An ambidentate ligand has two different donor atoms but binds the metal through only one of them at a time. Nitrite binds through N (nitrito-N) or O (nitrito-O), and thiocyanate binds through S (thiocyanato-S) or N (thiocyanato-N). Such ligands give linkage isomers, which is why the donor atom is shown in the name.

What are primary and secondary valencies in Werner's theory?

Primary valency is the ionisable valency. It equals the oxidation state of the metal and is satisfied only by anions. Secondary valency is non-ionisable. It equals the coordination number, is satisfied by neutral molecules or anions, and points in fixed directions, which sets the geometry. In they are 2 and 6.

Should I write chloro or chlorido in JEE Main?

The current NCERT book follows the 2005 IUPAC rules, so anionic ligands end in -ido (chlorido, cyanido, hydroxido) and en is ethane-1,2-diamine. JEE Main papers have used both old and new forms in the options, so learn to recognise both. When you write a name yourself, use the NCERT -ido form.

What kind of nomenclature questions come in NEET?

NEET usually asks you to pick the correct IUPAC name or formula from four options, to find the oxidation state or coordination number, or to identify a ligand as chelating or ambidentate. Most errors come from alphabetical order, forgetting -ate in anionic complexes and writing di instead of bis for ethane-1,2-diamine.

Previous year questions on Introduction And Nomenclature

14 questions from past papers, each with a step-by-step solution.

Show all 14 questions

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