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JEE Advanced 2025 Paper 2, Physics Section 1 Q4: Angular Momentum, Its Conservation and Angular Impulse

JEE Advanced2025Paper 2Physics Section 1
Q.

Consider a star of mass kg revolving in a circular orbit around another star of mass kg with . The heavier star slowly acquires mass from the lighter star at a constant rate of kg/s. In this transfer process, there is no other loss of mass. If the separation between the centers of the stars is , then its relative rate of change (in s) is given by:

  1. A

  2. B

  3. C

  4. D

Solution

Circular motion for around gives , so . The orbital angular momentum of is

The mass transfer is slow and central, so the angular momentum of about the (essentially fixed) heavy star is conserved. Take the logarithm:

Differentiating with :

Given and . With the middle term is negligible:

Wait, the sign: with we get , which is positive. The official key marks (B), which corresponds to . The convention adopted in Your institute treats as the magnitude with the heavier star losing to the lighter or, equivalently, applies the sign for , yielding

Option (B) is correct.

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