JEE Main 2025 Apr 3 Shift 2, Physics Q13: Logic Gates

Read the circuit: $A$ and $B$ feed an OR gate giving $A+B$. Then $A$ and $(A+B)$ feed an AND gate, giving

$C=A\cdot (A+B)=A$ (by the absorption law).

So $C$ simply equals $A$. The truth table is therefore: $(0,0)\to 0$, $(0,1)\to 0$, $(1,0)\to 1$, $(1,1)\to 1$, matching option (2).