JEE Main 2025 Apr 4 Shift 2, Chemistry Q23: Isomerism In Co-ordination Compounds

JEE Main2025Apr 4, Shift 2Chemistry

A metal complex with a formula $M C l_{4} \cdot 3 N H_{3}$ is involved in $s p^{3} d^{2}$ hybridisation. It upon reaction with excess of $A g N O_{3}$ solution gives ' $x$ ' moles of AgCl. Consider ' $x$ ' is equal to the number of lone pairs of electron present in central atom of $B r F_{5}$ . Then the number of geometrical isomers exhibited by the complex is ________.

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Solution

Find x: $B r F_{5}$ has the central Br using $s p^{3} d^{2}$ hybridisation with five Br-F bonds and one lone pair (square pyramidal geometry). Hence $x = 1$ .

So one mole of AgCl is precipitated, meaning the complex contains exactly one ionisable chloride and three chlorides bound inside the coordination sphere. The complex is therefore $[M (N H_{3})_{3} C l_{3}] C l$ , an octahedral $M a_{3} b_{3}$ type.

An octahedral $M a_{3} b_{3}$ complex exhibits two geometrical isomers:

(i) facial (fac): the three identical ligands occupy one triangular face of the octahedron;

(ii) meridional (mer): the three identical ligands lie along a meridian.

$∴$ Number of geometrical isomers = 2.

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JEE Main 2025 Apr 4 Shift 2, Chemistry Q23: Isomerism In Co-ordination Compounds

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