JEE Main 2025 Apr 7 Shift 1, Chemistry Q16: Valence Shell Electron Pair Repulsion (VSEPR) Theory

JEE Main2025Apr 7, Shift 1Chemistry

Match the LIST-I with LIST-II.

LIST-I (Molecule/ion)	LIST-II (Bond pair : lone pair on the central atom)
A. ICl $_{2}^{-}$	I. 4 : 2
B. H $_{2}$ O	II. 4 : 1
C. SO $_{2}$	III. 2 : 3
D. XeF $_{4}$	IV. 2 : 2

Choose the correct answer from the options given below :

A
A-IV, B-III, C-II, D-I
B
A-III, B-IV, C-II, D-I
C
A-III, B-IV, C-I, D-II
D
A-II, B-I, C-IV, D-III

Solution

Count bond pairs (BP) and lone pairs (LP) on the central atom for each species using VSEPR.

A. ICl $_{2}^{-}$ : Central I has 7 valence electrons, plus 1 (anion charge) = 8. Two I $-$ Cl bonds use 2 pairs (BP = 2); remaining 3 pairs are lone pairs (LP = 3). Geometry: linear. $\Rightarrow$ 2 : 3 (III)

B. H $_{2}$ O: O has 6 valence electrons. Two O $-$ H bonds (BP = 2); 2 lone pairs (LP = 2). Geometry: bent. $\Rightarrow$ 2 : 2 (IV)

C. SO $_{2}$ : S has 6 valence electrons; bonded to two O atoms by double bonds. Counting $σ$ + $π$ bonds gives 4 bond pairs around S; one lone pair remains. $\Rightarrow$ 4 : 1 (II)

D. XeF $_{4}$ : Xe has 8 valence electrons. Four Xe $-$ F bonds (BP = 4); remaining 4 electrons form 2 lone pairs (LP = 2). Geometry: square planar. $\Rightarrow$ 4 : 2 (I)

Matching: A $-$ III, B $-$ IV, C $-$ II, D $-$ I $\Rightarrow$ Option (2).

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JEE Main 2025 Apr 7 Shift 1, Chemistry Q16: Valence Shell Electron Pair Repulsion (VSEPR) Theory

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