JEE Advanced 2024 — Paper 1 — CHEM-IV solution

JEE Advanced2024Paper 1CHEM-IV

Based on VSEPR model, match the xenon compounds given in List-I with the corresponding geometries and the number of lone pairs on xenon given in List-II and choose the correct option.

List-I	List-II
(P) XeF $_{2}$	(1) Trigonal bipyramidal and two lone pair of electrons
(Q) XeF $_{4}$	(2) Tetrahedral and one lone pair of electrons
(R) XeO $_{3}$	(3) Octahedral and two lone pair of electrons
(S) XeO $_{3}$ F $_{2}$	(4) Trigonal bipyramidal and no lone pair of electrons
	(5) Trigonal bipyramidal and three lone pair of electrons

A
P-5, Q-2, R-3, S-1
B
P-5, Q-3, R-2, S-4
C
P-4, Q-3, R-2, S-1
D
P-4, Q-2, R-5, S-3

Solution

XeF $_{2}$ : 2 bond pairs + 3 lone pairs on Xe (5 electron pairs). Hybridisation $s p^{3} d$ , electron geometry trigonal bipyramidal, molecular shape linear. Trigonal bipyramidal with 3 lone pairs. P $\to$ 5.

XeF $_{4}$ : 4 bond pairs + 2 lone pairs (6 pairs). $s p^{3} d^{2}$ , electron geometry octahedral, molecular shape square planar. Octahedral with 2 lone pairs. Q $\to$ 3.

XeO $_{3}$ : 3 Xe=O bonds + 1 lone pair (4 electron domains). $s p^{3}$ , electron geometry tetrahedral, molecular shape pyramidal. Tetrahedral with 1 lone pair. R $\to$ 2.

XeO $_{3}$ F $_{2}$ : 3 Xe=O + 2 Xe-F bonds, no lone pair on Xe (5 electron domains). $s p^{3} d$ . Trigonal bipyramidal with no lone pairs. S $\to$ 4.

$∴$ Option (B).

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