JEE Main 2025 Jan 28 Shift 1, Chemistry Q10: Valence Shell Electron Pair Repulsion (VSEPR) Theory

Apply VSEPR to each species:

BrF${}_5$: Br has 5 bond pairs and 1 lone pair (AX${}_5$E). Geometry is square pyramidal.

XeOF${}_4$: Xe has 5 bond pairs (4 to F, 1 to O) and 1 lone pair (AX${}_5$E). Geometry is square pyramidal.

SbF${}_5$: Sb has 5 bond pairs and 0 lone pairs (AX${}_5$). Geometry is trigonal bipyramidal.

PCl${}_5$: P has 5 bond pairs and 0 lone pairs (AX${}_5$). Geometry is trigonal bipyramidal.

$\therefore$ Only BrF${}_5$ and XeOF${}_4$ are square pyramidal.