JEE Main 2025 Jan 22 Shift 1, Chemistry Q22: Qualitative and Quantitative Analysis

JEE Main2025Jan 22, Shift 1Chemistry

In Carius method for estimation of halogens, 180 mg of an organic compound produced 143.5 mg of AgCl. The percentage composition of chlorine in the compound is _______ %.

[Given : molar mass in g mol $^{- 1}$ of Ag : 108, Cl = 35.5]

Your answer

Solution

Molar mass of AgCl $= 108 + 35.5 = 143.5$ g/mol.

Moles of AgCl produced $= \frac{143.5 \times 1 0 ^{- 3}}{143.5} = 1 0^{- 3}$ mol $=$ moles of Cl in the sample.

Mass of Cl $= 1 0^{- 3} \times 35.5 = 35.5 \times 1 0^{- 3}$ g.

% Cl $= \frac{35.5 \times 1 0 ^{- 3}}{180 \times 1 0 ^{- 3}} \times 100 \approx 19.72%$ , which rounds to $20%$ .

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JEE Main 2025 Jan 22 Shift 1, Chemistry Q22: Qualitative and Quantitative Analysis

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