JEE Main 2025 Jan 29 Shift 1, Physics Q25: Motion In Two And Three Dimension

JEE Main2025Jan 29, Shift 1Physics

The maximum speed of a boat in still water is $27 km/h .$ Now this boat is moving downstream in a river flowing at $9 km/h .$ A man in the boat throws a ball vertically upwards with speed of $10 m/s .$ Range of the ball as observed by an observer at rest on the river bank, is ______ cm.

(Take $g = 10 m/ s^{2}$ )

Your answer

Solution

The ground-frame horizontal velocity of the ball equals the velocity of the boat (since the ball is thrown straight up relative to the boat). Downstream speed of boat $= 27 + 9 = 36 km/h = 10 m/s .$

Time of flight (vertical motion): $T = \frac{2 u}{g} = \frac{2 \cdot 10}{10} = 2 s .$

Horizontal range $= 10 m/s \times 2 s = 20 m = 2000 cm .$

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JEE Main 2025 Jan 29 Shift 1, Physics Q25: Motion In Two And Three Dimension

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