JEE Main 2025 Jan 29 Shift 2, Chemistry Q23: Properties and Important Reactions of Aldehydes & Ketones

JEE Main2025Jan 29, Shift 2Chemistry

In the Claisen-Schmidt reaction to prepare, dibenzalacetone from 5.3 g benzaldehyde, a total of 3.51 g of product was obtained. The percentage yield in this reaction was ______ %.

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Solution

The Claisen-Schmidt condensation: $2 P h C H O + (C H_{3})_{2} C O base P h C H = C H - C O - C H = C H P h$ (dibenzalacetone, $M = 234$ g $m o l^{- 1}$ ).

Moles of benzaldehyde used $= \frac{5.3}{106} = 0.05$ mol.

Stoichiometry uses $2$ mol $P h C H O$ per $1$ mol product, so theoretical product $= \frac{0.05}{2} = 0.025$ mol.

Actual product $= \frac{3.51}{234} = 0.015$ mol.

$% yield = \frac{0.015}{0.025} \times 100 = 60%$ .

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JEE Main 2025 Jan 29 Shift 2, Chemistry Q23: Properties and Important Reactions of Aldehydes & Ketones

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