JEE Main 2026 — Apr 5, Shift 1 — Physics solution

JEE Main2026Apr 5, Shift 1Physics

$L$ , $C$ and $R$ represents physical quantities inductance, capacitance and resistance respectively.

The dimensional formula $M L^{2} T^{- 4} A^{- 2}$ corresponds to ________.

A
$\frac{R}{L C}$
B
$\frac{R}{L C}$
C
$\frac{C}{L R}$
D
$\frac{1}{R} \frac{L}{C}$

Solution

Recall that $L C$ has the dimension of $T^{2}$ (the LC oscillation period), and $R$ has dimensions $[M L^{2} T^{- 3} A^{- 2}]$ .

Therefore $\frac{R}{L C}$ has dimensions $\frac{M L ^{2} T ^{- 3} A ^{- 2}}{T} = M L^{2} T^{- 4} A^{- 2}$ , matching the target.

Quick check on the others: $\frac{R}{L C}$ gives $M L^{2} T^{- 5} A^{- 2}$ ; $\frac{1}{R} L / C$ is dimensionless (both numerator and denominator have impedance dimensions). Only option (1) fits.

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