JEE Main 2026 — Apr 5, Shift 1 — Physics solution

JEE Main2026Apr 5, Shift 1Physics

A displacement current of 4.0 A can be set up in the space between two parallel plates of $6 μ$ F capacitor. The rate of change of potential difference across the plates of the capacitor is nearly $α \times 1 0^{6}$ V/s. The value of $α$ is _______.

A
0.58
B
0.67
C
0.82
D
0.75

Solution

Displacement current through a capacitor obeys $I_{d} = C \frac{d V}{d t}$ .

$4 = (6 \times 1 0^{- 6}) \frac{d V}{d t} \Rightarrow \frac{d V}{d t} = \frac{2}{3} \times 1 0^{6} \approx 0.67 \times 1 0^{6}$ V/s.

So $α \approx 0.67$ .

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