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JEE Main2026Apr 5, Shift 1Chemistry
Q.

"P" is a hydrocarbon of molecular formula . On ozonolysis, "P" forms "Q". "Q" on treatment with alkali under reflux condition produces "R", which on treatment with gives a yellow precipitate. Acidification of the solution gives "S". The structure of "S" is given below :

The correct structure of "P" is

  1. A
  2. B
  3. C
  4. D
Solution

Work backward from S. The ring in S is five-membered with one alkene-COOH and one alkene-CH. So R is a cyclopentenyl methyl ketone (formed by intramolecular aldol condensation of Q) that on haloform reaction (I/NaOH) loses the methyl group as CHI and, after acidification, leaves the carboxylic acid S.

This means Q is a 1,6-dicarbonyl (a diketone or a keto-aldehyde) capable of intramolecular aldol cyclisation to the five-membered ring. Ozonolysis of P must produce that 1,6-dicarbonyl.

The precursor that cleanly fits is 1,2-dimethylcyclohex-1-ene: ozonolysis cleaves the ring at the internal alkene, generating a 1,6-diketone (with both carbonyls -substituted by methyls). Intramolecular aldol condensation gives the methylcyclopentenyl ketone R, then haloform/acidification delivers S.

Therefore P is 1,2-dimethylcyclohex-1-ene.

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