JEE Main 2026 Jan 28 Shift 1, Chemistry Q15: Mechanism of Some Important Reactions of Alkenes

JEE Main2026Jan 28, Shift 1Chemistry

$Ph - CH = CH_{2} (PhCOO)_{2} HBr Product$

Consider the above reaction

A. The reaction proceeds through a more stable radical intermediate.

B. The role of peroxide is to generate $\dot{H}$ (Hydrogen radical).

C. During this reaction, benzene is formed as a biproduct.

D. 1-Bromo-2-phenylethane is fanned as the minor product.

E. The same reaction in absence of peroxide proceeds via carbocation intermediate.

Identify the correct statements. Choose the correct answer from the options given below:

Solution

$Ph - CH = CH_{2} (PhCOO)_{2} HBr Ph - CH_{2} - CH_{2} - Br$

Anti-Markovnikov addition

• In the presence of peroxide, the reaction proceeds through a free-radical mechanism.

• In the absence of peroxide, the reaction follows a carbocation mechanism (Markovnikov addition).

• Benzene is also obtained as a by-product.

Concept behind this question

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