JEE Main 2026 Apr 6 Shift 1, Physics Q3: Work Energy Theorem And Its Applications

JEE Main2026Apr 6, Shift 1Physics

The rain drop of mass $1$ g, starts with zero velocity from a height of $1$ km. It hits the ground with a speed of $5$ m/s. The work done by the unknown resistive force is __________ J. (take $g = 10$ m/s $^{2}$ )

A
$- 8.75$
B
$- 8.35$
C
$- 9.55$
D
$- 9.98$

Solution

By the work-energy theorem, $W_{gravity} + W_{res} = Δ K E$ .

$W_{res} = \frac{1}{2} m v^{2} - m g h = \frac{1}{2} (1 0^{- 3}) (5)^{2} - (1 0^{- 3}) (10) (1000)$ .

$= 0.0125 - 10 = - 9.9875 \approx - 9.98$ J.

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JEE Main 2026 Apr 6 Shift 1, Physics Q3: Work Energy Theorem And Its Applications

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