JEE Main 2026 Apr 6 Shift 1, Chemistry Q13: Purification Methods

JEE Main2026Apr 6, Shift 1Chemistry

$R_{f}$ value for 2-methylpropene in a solvent system (Ethyl acetate + ether) is $0.42$ . 2-methylpropene is treated with dilute $H_{2} SO_{4}$ to give major organic product (X). $R_{f}$ value for (X) in the same solvent system under identical condition will be:

A
$0.42$
B
$0.82$
C
$0.62$
D
$0.12$

Solution

2-Methylpropene $(CH_{3})_{2} C = CH_{2}$ undergoes acid-catalysed hydration following Markovnikov's rule. The carbocation forms preferentially at the more substituted carbon, giving tert-butanol $(CH_{3})_{3} C -OH$ as the major product (X).

$R_{f}$ in a moderately polar solvent system is inversely related to the analyte's polarity: more polar compounds adsorb more strongly to the silica stationary phase and travel less. The alcohol X is significantly more polar than the parent alkene.

$∴ R_{f} (X) < 0.42$ , and among the choices, $0.12$ fits.

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JEE Main 2026 Apr 6 Shift 1, Chemistry Q13: Purification Methods

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