JEE Main 2026 Apr 6 Shift 1, Chemistry Q22: Diazonium Salt

JEE Main2026Apr 6, Shift 1Chemistry

Consider the following sequence of reactions.

The percentage of nitrogen in the yellow product (X) formed is ______ %. (Nearest Integer)

(Given Molar mass in g mol $^{- 1}$ : H : 1, C : 12, N : 14)

Your answer

Solution

Under HCl in the presence of excess aniline at $40$ - $4 5^{\circ}$ C, diazoaminobenzene (Ph-N=N-NH-Ph) undergoes acid-catalysed rearrangement (the well-known diazoamino-to-aminoazo rearrangement) to give p-aminoazobenzene, $Ph-N=N-C_{6} H_{4} -NH_{2}$ (para), which is the characteristic yellow product.

Molecular formula of $p$ -aminoazobenzene: $C_{12} H_{11} N_{3}$ , molar mass $= 12 (12) + 11 (1) + 3 (14) = 144 + 11 + 42 = 197$ g mol $^{- 1}$ .

Mass of N $= 42$ ; mass $%$ of N $= \frac{42}{197} \times 100 = 21.32%$ .

$∴$ nearest integer is $21$ .

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JEE Main 2026 Apr 6 Shift 1, Chemistry Q22: Diazonium Salt

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